# Can you solve this equation?

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;

InputThe first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);OutputFor each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.Sample Input

2
100
-4

Sample Output

1.6152
No solution!

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
#define eps 1e-8

int findx(double x,double y)
{
if(y-(8.0*pow(x,4)+7.0*pow(x,3)+2.0*pow(x,2)+3.0*x+6)<0)
return 1;
else
return 0;
}

int main(){
double y;
int a;
cin>>a;
while(a--){
cin>>y;
if((807020306)<y||y<6){
cout<<"No solution!"<<endl;

}else{
//8*x^4+7*x^3+2*x^2+3*x+6==Y
double l=0.0;
double r=100.0;
double mid=50.0;
while(l+eps<r){
if(findx(mid,y)){
r=mid;
mid=(l+r)/2;
}else{
l=mid;
mid=(l+r)/2;
}

}

printf("%.4lf\n",l);
}
}

return 0;
}